HackerRank Max Min Problem Solution

In this post, we will solve HackerRank Max Min Problem Solution.

You will be given a list of integers, arr, and a single integer k. You must create an array of length & from elements of arr such that its unfairness is minimized. Call that array arr. Unfairness of an array is calculated as
max(arr) – min(arr’)
Where:

max denotes the largest integer in arr. – min denotes the smallest integer in arr’.

Example
arr = [1, 4, 7, 2]
k = 2
Pick any two elements, say arr’ = [4, 7].
un fairness = max(4,7) min(4,7) =7-4=3
Testing for all pairs, the solution [1, 2] provides the minimum unfairness.
Note: Integers in arr may not be unique.

Function Description

Complete the maxMin function in the editor below.
maxMin has the following parameter(s):

int k: the number of elements to select
int arr[n]:: an array of integers

Returns

int: the minimum possible unfairness

Input Format

The first line contains an integer n, the number of elements in array arr.
The second line contains an integer k.

Sample Input 0

Sample Output 0

Max Min C Solution

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int comparator(const void *a, const void *b)
{return ( *(int*)a - *(int*)b );
}
int main() {
    int n,k,i;
    
    k=0;
    n=0;
    scanf("%d",&n);
    scanf("%d",&k);
    int a[n];
    for(i=0;i<n;i++)
    {  
       a[i]=0;
    
    
    }
    
    
    for(i=0;i<n;i++)
    {  int num;
       scanf("%d",&num);
       a[i]=num;
    }
    
    qsort(a,n, sizeof(int), comparator);
    
    int min=10000000000;
    for(i=0;i<n-k+1;i++)
    { int loc=a[i+k-1]-a[i];
      if(loc<min)
      {min=loc;}
    }
   // printf("%d%d",n,k);
    printf("%d",min);
}

Max Min C++ Solution

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;


int main() {
    /* Enter your code here. Read input from STDIN. Print output to STDOUT */
    long n;
    long k;
    vector<long> a;
    long x;
    cin>>n>>k;
    for(long i=0;i<n;i++){
        cin>>x;
        a.push_back(x);
    }
    sort(a.begin(),a.end());
    long d;
    x=a[n-1];
    for(long i=0;i<n-k+1;i++){
        d = a[i+k-1]-a[i];
        //cout<<a[i]<<"---"<<a[(i+k-1)]<<":"<<d<<" "<<endl;
        if(x>d){
            x=d;
        }
    }
    cout<<x<<endl;
    return 0;
}

Max Min C Sharp Solution

using System;

using System.Collections.Generic;

using System.Linq;

using System.Text;

using System.Threading.Tasks;



namespace AngryChildren

{

    class Program

    {

        static void Main(string[] args)

        {

            int n; n = int.Parse(Console.ReadLine());

            int k; k = int.Parse(Console.ReadLine()); k--;

            int[] candy = new int[n];

            for (int i = 0; i < n; i++)

            {

                candy[i] = int.Parse(Console.ReadLine());

            }



            Array.Sort(candy);

            int minimumUnfairness = 1000000000;



            for (int i = 0; i < n - k; i++)

            {

                int unfairness = candy[i + k] - candy[i];

                if (unfairness < minimumUnfairness)

                    minimumUnfairness = unfairness;

            }



            Console.WriteLine(minimumUnfairness);

        }

    }

}

Max Min Java Solution

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.function.*;
import java.util.regex.*;
import java.util.stream.*;
import static java.util.stream.Collectors.joining;
import static java.util.stream.Collectors.toList;

class Result {

    /*
     * Complete the 'maxMin' function below.
     *
     * The function is expected to return an INTEGER.
     * The function accepts following parameters:
     *  1. INTEGER k
     *  2. INTEGER_ARRAY arr
     */

    public static int maxMin(int k, List<Integer> arr) {
    // Write your code here
    Collections.sort(arr);
    int ans = Integer.MAX_VALUE;
    for(int i = 0 ; i < arr.size() - k+1 ; i ++){
       // System.out.println(arr.get(i+k-1) +" "+ arr.get(i));
        ans = Math.min(ans,arr.get(i+k-1) - arr.get(i));
    }
    return ans;
    
    }

}

public class Solution {
    public static void main(String[] args) throws IOException {
        BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));
        BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));

        int n = Integer.parseInt(bufferedReader.readLine().trim());

        int k = Integer.parseInt(bufferedReader.readLine().trim());

        List<Integer> arr = IntStream.range(0, n).mapToObj(i -> {
            try {
                return bufferedReader.readLine().replaceAll("\\s+$", "");
            } catch (IOException ex) {
                throw new RuntimeException(ex);
            }
        })
            .map(String::trim)
            .map(Integer::parseInt)
            .collect(toList());

        int result = Result.maxMin(k, arr);

        bufferedWriter.write(String.valueOf(result));
        bufferedWriter.newLine();

        bufferedReader.close();
        bufferedWriter.close();
    }
}

Max Min JavaScript Solution

var input = '';
process.stdin.resume()
process.stdin.on("data", function (i) {
  input = input + i;
});
process.stdin.on("end", function () {
  input = input.split("\n");
  var N = parseInt(input.shift());
  var K = parseInt(input.shift());
  var a = [];
  for (i in input) {
    a.push(parseInt(input[i]));
  }
  a.sort(function(a,b){return a - b;});
  var u = -1;
  for (i=0;i<a.length-K;i++) {
    var d = a[i+K-1] - a[i];
    if (u > d) u = d;
    if (u === -1) u = d;
  }
  //console.log(a);
  console.log(u);
});

Max Min Python Solution

import bisect

N = int(input())
K = int(input())

cookies = [];

for i in range(N):
    bisect.insort_left(cookies, int(input()))

sol = float('inf');

sol = min([cookies[i+K-1] - cookies[i] for i in range(N-K+1)])
          
print (sol)

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