HackerRank Mini-Max Sum Problem Solution Yashwant Parihar, April 10, 2023April 11, 2023 In this post, We are going to solve HackerRank Mini-Max Sum Problem. Given five positive integers, find the minimum and maximum values that can be calculated by summing exactly four of the five integers. Then print the respective minimum and maximum values as a single line of two space-separated long integers.Examplearr = [ 1, 3, 5, 7, 9]The minimum sum is 1 + 3 + 5 + 7 = 16 and the maximum sum is 3 + 5 + 7 + 9 = 24The function prints16 24Function DescriptionComplete the miniMaxSum function in the editor below.miniMaxSum has the following parameter(s):arr: an array of 5 integersPrintPrint two space-separated integers on one line: the minimum sum and the maximum sum of 4 of 5 elements.Input FormatA single line of five space-separated integers.Constraints1 < arr [I] < 10 power 9Output FormatPrint two space-separated long integers denoting the respective minimum and maximum values that can be calculated by summing exactly four of the five integers. (The output can be greater than a 32 bit integer.)Sample Input1 2 3 4 5 Sample Output10 14HackerRank-Mini-Max-Sum-Problem-SolutionMini-Max Sum C Solution#include <stdio.h> #include <string.h> #include <math.h> #include <stdlib.h> int main() { long long int a[5],temp; int i, j; scanf("%lld %lld %lld %lld %lld",&a[0],&a[1],&a[2],&a[3],&a[4]); for (i=1;i<=4;i++) { j=i; while (j>0 && (a[j-1] > a[j])) { temp= a[j]; a[j]= a[j-1]; a[j-1]=temp; j=j-1; } } long long int min=a[0]+a[1]+a[2]+a[3]; long long int max=a[1]+a[2]+a[3]+a[4]; printf("%lld %lld",min,max); return 0; }Mini-Max Sum C++ Solution #include<bits/stdc++.h> using namespace std; int main() { long long a[5]; cin>>a[0]>>a[1]>>a[2]>>a[3]>>a[4]; sort(a,a+5); cout<<a[0]+a[1]+a[2]+a[3]<<" "<<a[4]+a[1]+a[2]+a[3]<<endl; return 0; }Mini-Max Sum C Sharp Solutionusing System; using System.Collections.Generic; using System.IO; class Solution { static void Main(String[] args) { string[] arr = Console.ReadLine().Split(' '); long sum = 0; List<long> dizi = new List<long>(); for (int i = 0; i < arr.Length; i++) { long temp = Convert.ToInt64(arr[i]); dizi.Add(temp); } for (int i = 0; i < dizi.Count; i++) { sum = sum + dizi[i]; } for (int i = 0; i < dizi.Count - 1; i++) { for (int j = 1; j < dizi.Count - i; j++) { if (dizi[j] < dizi[j - 1]) { long gecici = dizi[j - 1]; dizi[j - 1] = dizi[j]; dizi[j] = gecici; } } } long max = sum - dizi[0]; long min = sum - dizi[4]; Console.WriteLine("{0} {1}", min, max); Console.ReadKey(); } }Mini-Max Sum Java Solutionimport java.io.*; import java.math.*; import java.security.*; import java.text.*; import java.util.*; import java.util.concurrent.*; import java.util.function.*; import java.util.regex.*; import java.util.stream.*; import static java.util.stream.Collectors.joining; import static java.util.stream.Collectors.toList; class Result { /* * Complete the 'miniMaxSum' function below. * 256741038 623958417 467905213 714532089 938071625 2063136757 2744467344 * The function accepts INTEGER_ARRAY arr as parameter. */ public static void miniMaxSum(List<Integer> arr) { int max = -1; int min = Integer.MAX_VALUE; ; long sumMax = 0; long sumMin = 0; long sum = 0; int numberChecked =0; for(int el : arr){ max = Math.max(el,max); min = Math.min(el,min); sum+=el; } if(min==max){ System.out.print(sum -max); System.out.print(" "); System.out.print(sum -max); return; } for(int el : arr){ if(el!=max) sumMin+=el; if(el!=min) sumMax+=el; } System.out.print(sumMin); System.out.print(" "); System.out.print(sumMax); } } public class Solution { public static void main(String[] args) throws IOException { BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in)); List<Integer> arr = Stream.of(bufferedReader.readLine().replaceAll("\\s+$", "").split(" ")) .map(Integer::parseInt) .collect(toList()); Result.miniMaxSum(arr); bufferedReader.close(); } }Mini-Max Sum JavaScript Solutionprocess.stdin.resume(); process.stdin.setEncoding('ascii'); var input_stdin = ""; var input_stdin_array = ""; var input_currentline = 0; process.stdin.on('data', function (data) { input_stdin += data; }); process.stdin.on('end', function () { input_stdin_array = input_stdin.split("\n"); main(); }); function readLine() { return input_stdin_array[input_currentline++]; } /////////////// ignore above this line //////////////////// Array.prototype.min = function () { var min = 777777777777; for (var i = 0; i < this.length; i++) { if (this[i] < min) min = this[i]; } return min; } Array.prototype.max = function () { var max = 0; for (var i = 0; i < this.length; i++) { if (this[i] > max) max = this[i]; } return max; } Array.prototype.sum = function () { return this.reduce((x, y) => { return x + y;}); } function main() { var vals = readLine().split(' ').map((i) => {return parseInt(i);}); //console.log(vals); var lo = vals.sum() - vals.max(); var hi = vals.sum() - vals.min(); console.log(lo.toString() + ' ' + hi.toString()) }Mini-Max Sum Python Solutiondef swap(arr,x,y): mem = arr[x] arr[x] = arr[y] arr[y] = mem return arr def qsort(ar,start,end): # base case if end-start <= 0: return ar # pivot pivot = ar[end] # init index for pivot ind = start # loop less final value (pivot) for i in range(start,end): if ar[i] <= pivot: ar = swap(ar,i,ind) ind += 1 else: pass swap(ar,ind,end) # left side ar = qsort(ar,start,ind-1) # right side ar = qsort(ar,ind+1,end) return ar ar=[int(a) for a in input().strip().split(" ")] ar=qsort(ar,0,len(ar)-1) print(sum(ar[:4]), sum(ar[1:])) Other SolutionsHackerRank Birthday Cake Candles SolutionHackerRank Time Conversion Problem Solution c C# C++ HackerRank Solutions java javascript python CcppCSharpHackerrank Solutionsjavajavascriptpython