In this post, We are going to solve HackerRank Simple Array Sum Problem. Given an array of integers, find the sum of its elements.
For example, if the array ar=[1,2,3], 1 + 2 + 3 = 6, so return 6 .
Function Description
Complete the simpleArraySum function in the editor below. It must return the sum of the array elements as an integer.
simpleArraySum has the following parameter(s):
- ar: an array of integers
Input Format
The first line contains an integer, n, denoting the size of the array.
The second line contains space-separated integers representing the array’s elements.
Constraints
0 < n, ar [I] < 1000
Output Format
Print the sum of the array’s elements as a single integer.
Sample Input
6
1 2 3 4 10 11
Sample Output
31
Explanation
We print the sum of the array’s elements:
1 + 2 + 3 + 4 + 10 + 11 = 31.
Simple Array Sum C Solution
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int main()
{
int *a,n,i,ans=0;
scanf("%d",&n);
a=(int *)malloc(sizeof(int)*n);
for(i=0;i<n;i++)
scanf("%d",&a[i]);
for(i=0;i<n;i++)
ans=ans+a[i];
printf("%d",ans);
return 0;
}Simple Array Sum C++ Solution
#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
int main() {
unsigned nb;
unsigned tot = 0;
cin >> nb;
for (int i = 0; i < nb; i++) {
int num;
cin>>num;
tot += num;
}
cout << tot;
return 0;
}Simple Array Sum Java Solution
import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.function.*;
import java.util.regex.*;
import java.util.stream.*;
import static java.util.stream.Collectors.joining;
import static java.util.stream.Collectors.toList;
class Result {
/*
* Complete the 'simpleArraySum' function below.
*
* The function is expected to return an INTEGER.
* The function accepts INTEGER_ARRAY ar as parameter.
*/
public static int simpleArraySum(List<Integer> ar) {
return ar.stream().mapToInt(i -> i).sum();
}
}
public class Solution {
public static void main(String[] args) throws IOException {
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));
BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));
int arCount = Integer.parseInt(bufferedReader.readLine().trim());
List<Integer> ar = Stream.of(bufferedReader.readLine().replaceAll("\\s+$", "").split(" "))
.map(Integer::parseInt)
.collect(toList());
int result = Result.simpleArraySum(ar);
bufferedWriter.write(String.valueOf(result));
bufferedWriter.newLine();
bufferedReader.close();
bufferedWriter.close();
}
}Simple Array Sum Javascript Solution
function processData(input) {
//Enter your code here
var result = 0,
lines = input.split('\n'),
size = parseInt(lines[0]),
digits = lines[1].trim().split(" ").slice(0, size);
while (digits.length){
result += parseInt(digits.pop(), 10);
}
console.log(result);
return result;
}
process.stdin.resume();
process.stdin.setEncoding("ascii");
_input = "";
process.stdin.on("data", function (input) {
_input += input;
});
process.stdin.on("end", function () {
processData(_input);
});Simple Array Sum Python Solution
def counting(number, split):
total = 0
for i in range(0, number):
total += int(split[i])
return total
num = int(input())
array = input().split()
print(counting(num, array))Other Solutions
