HackerRank Tree Splitting Problem Solution

HackerRank Tree Splitting Problem Solution

Yashwant Parihar,

In this post, we will solve HackerRank Tree Splitting Problem Solution.

Given a tree with vertices numbered from 1 to n. You need to process m queries. Each query represents a vertex number encoded in the following way:
Queries are encoded in the following way: Let. m, be the jth query and ans, be the
answer for the jth query where 1 <j< m and anso is always 0. Then vertex vjansj 1 mj. We are assure that v, is between 1 and n, and hasn’t been removed before.
Note: is the bitwise XOR operator.
For each query, first decode the vertex v and then perform the following:

  1. Print the size of the connected component containing v.
  2. Remove vertex v and all edges connected to v.

Input Format
The first line contains a single integer. n. denoting the number of vertices in the tree. Each line of the n-1 subsequent lines (where 0 < i < n) contains 2 space-separated integers describing the respective nodes, u, and u,, connected by edge i. The next line contains a single integer, m, denoting the number of queries. Each line j of the m subsequent lines contains a single integer, vertex number mj.

Output Format

For each query, print the size of the corresponding connected component on a new line.

Sample Input 0

3
1 2
1 3
3
1
1
2

Sample Output 0

3
1
1

Sample Input 1

4
1 2
1 3
1 4
4
3
6
2
6

Sample Output 1

4
3
2
1
HackerRank Tree Splitting Problem Solution
HackerRank Tree Splitting Problem Solution

Tree Splitting C Solution

#include <stdlib.h>
#include <stdio.h>

struct Set {
    int count;
};

typedef struct Set Set;

struct node{
    int number;
    struct node * parent;
    struct node * next;
    struct node * prev;
    struct node * first_child;
    Set * set;
};

typedef struct node node;

void print_children(node * n){
    node * child = n->first_child;
    while(child){
        printf("%d\n", child->number);
        child = child->next;
    }
}

void add_child(node * n, node * c){
    node * cur = n->first_child;
    n->first_child = c;
    if (cur){
        cur->prev = c;
        c->next = cur;
    }
}

void fill_children(node * root, node ** nodes, node ** result_nodes){
    node * repr = nodes[root->number];
    if(repr == 0){
        return;
    }
    node * child = repr->first_child;
    while(child){
        if (result_nodes[child->number] != 0){
            child = child->next;
            continue;
        }
        node * c = calloc(1, sizeof(node));
        c->number = child->number;
        c->parent = root;
        result_nodes[c->number] = c;
        add_child(root, c);
        fill_children(c, nodes, result_nodes);
        child = child->next;
    }
}

void compute_below(node * root, Set * set) {
    if (set == 0) {
        set = calloc(1, sizeof(set));
    }
    root->set = set;
    set->count++;
    node * child = root -> first_child;
    while(child){
        compute_below(child, set);
        child = child->next;
    }
}

void remove_node(node * item) {
//    subtract_below(item, item->below+1);
    int everyChild = item->parent != 0;
    node * child = item->first_child;
    int childCount = 0;
    int toRemove = 1;
    while (child) {
        childCount++;
        if (everyChild || childCount > 1) {
            compute_below(child, 0);
            toRemove += child->set->count;
        }
        child->parent = 0;
        child = child->next;
    }
    item->set->count -= toRemove;
    node * parent = item->parent;
    if(parent){
        if(parent->first_child == item){
            parent->first_child = item->next;
        }
        if(item->next){
            item->next->prev = item->prev;
        }
        if(item->prev){
            item->prev->next = item->next;
        }
    }
}

int main(int argc, char **argv){
    int n;
    scanf("%d\n", &n);
    int i = 0;
    node ** nodes = calloc(n+1, sizeof(node *));
    for(i = 0; i < n-1; i++){
        int a,b;
        scanf("%d %d\n", &a, &b);
        node * node_a = nodes[a];
        if(node_a == 0) {
            node_a = calloc(1, sizeof(node));
            node_a->number = a;
            nodes[a] = node_a;
        }
        node * x = calloc(1, sizeof(node));
        x->number = b;
        add_child(node_a,x);
        
        node * node_b = nodes[b];
        if(node_b == 0){
            node_b = calloc(1, sizeof(node));
            node_b->number = b;
            nodes[b] = node_b;
        }
        x = calloc(1, sizeof(node));
        x->number = a;
        add_child(node_b, x);
    }
    
    node * root = calloc(1, sizeof(node));
    root->number = 1;
    node ** result_nodes = calloc(n+1, sizeof(node *));
    result_nodes[1] = root;
    fill_children(root, nodes, result_nodes);
    compute_below(result_nodes[1], 0);
    int ans = 0;
    int num_queries;
    scanf("%d\n", &num_queries);
    for(i = 0; i < num_queries; i++){
        int m;
        scanf("%d\n", &m);
        int q = m^ans;
        node * n = result_nodes[q];
        ans = n->set->count;
        printf("%d\n", ans);
        remove_node(n);
    }
    return 0;
}

Tree Splitting C++ Solution

#include<cstdio>
#include<ctime>
#include<cstdlib>
#include<vector>

using namespace std;

int INF, N, M, nr, V, v[400009], ap[200009], t[200009];
bool scos[200009];
vector<int> muchii[200009];

struct nod{
    int K, P, nr;
    nod *l, *r, *t;
    nod (int K, int P, int nr, nod *l, nod *r){
        this->nr = nr;
        this->l = l;
        this->r = r;
        this->P = P;
        this->K = K;
        this->t = 0;
    }
} *adresa1[200009], *adresa2[200009], *nil, *R;

int Rand(){
    return ((rand() % 32768) << 15) + (rand() % 32768) + 1;
}

void reup(nod *&n){
    if(n->l != nil) n->l->t = n;
    if(n->r != nil) n->r->t = n;
    n->nr = n->l->nr + n->r->nr + 1;
}

void rot_left(nod *&n){
    nod *t = n->l;
    n->l = t->r, t->r = n;
    t->t = n->t;
    reup(n);
    reup(t);
    n = t;
}

void rot_right(nod *&n){
    nod *t = n->r;
    n->r = t->l, t->l = n;
    t->t = n->t;
    reup (n);
    reup (t);
    n = t;
}

void balance(nod *&n){
    if(n->l->P > n->P)
        rot_left(n);
    else if(n->r->P > n->P)
        rot_right(n);
}

void Insert(nod *&n, int Poz, int K, int P){
    if(n == nil){
        n = new nod(K, P, 1, nil, nil);
        return;
    }
    if(n->l->nr >= Poz) Insert (n->l, Poz, K, P);
    else Insert(n->r, Poz - n->l->nr - 1, K, P);
    reup (n);
    balance (n);
}

void Erase(nod *&n, int Poz){
    if(n->l->nr >= Poz)
        Erase(n->l, Poz);
    else if(n->l->nr + 1 < Poz)
        Erase(n->r, Poz - n->l->nr - 1);
    else{
        if(n->l == nil && n->r == nil){
            delete n;
            n = nil;
        }
        else{
            if(n->l->P > n->r->P)
                rot_left (n);
            else
                rot_right (n);
            Erase(n, Poz);
        }
    }
    if(n != nil) reup (n);
}

void join(nod *&R, nod *&Rl, nod *&Rr){
    R = new nod(0, 0, Rl->nr + Rr->nr + 1, Rl, Rr);
    Erase(R, Rl->nr + 1);
}

void split(nod *&R, nod *&Rl, nod *&Rr, int Poz){
    Insert (R, Poz, 0, INF);
    Rl = R->l, Rl->t = 0;
    Rr = R->r, Rr->t = 0;
    delete R, R = nil;
}

bool nu_radacina(nod *&n){
    if(n->t != 0 && (n->t->l == n || n->t->r == n)) return 1;
    return 0;
}

void det_root(nod *n, nod *&R){
    while(1){
        if (nu_radacina(n))
            n = n->t;
        else
            break;
    }
    R = n;
}

int Get_Pos(nod *n){
    int ans = n->l->nr + 1;
    while (1){
        if (nu_radacina(n)){
            if(n->t->l == n) n = n->t;
            else ans += n->t->l->nr + 1, n = n->t;
        }
        else break;
    }
    return ans;
}

void dfs(int nod){
    ap[nod] = 1;
    v[++nr] = nod;
    for(vector<int>::iterator it = muchii[nod].begin(); it != muchii[nod].end(); it++)
        if (ap[*it] == 0){
            dfs(*it);
            t[*it] = nod;
        }
    v[++nr] = -nod;
}

void build(nod *&n){
    if(n == nil) return ;
    if(n->K < 0)
        adresa2[-n->K] = n;
    else
        adresa1[n->K] = n;
    build(n->l);
    build(n->r);
}

void afis(nod *&n){
    if (n == nil) return ;
    afis(n->l);
    printf("%d ", n->K);
    afis(n->r);
}

void Del(int a, int b){
    if(t[b] == a){
        int aux = a;
        a = b;
        b = aux;
    }
    nod *R, *R1, *R2, *R3, *R4;
    det_root(adresa1[a], R);
    int p1, p2;
    p1 = Get_Pos(adresa1[a]);
    p2 = Get_Pos(adresa2[a]);
    split(R, R4, R3, p2);
    split(R4, R1, R2, p1 - 1);
    R2->t = 0;
    join(R, R1, R3);
}

int main(){
    srand(time(0));
    INF = (1 << 30) + 7;
    scanf("%d", &N);
    for(int i = 1; i < N; i++){
        int X, Y;
        scanf("%d %d", &X, &Y);
        muchii[X].push_back(Y);
        muchii[Y].push_back(X);
    }
    dfs(1);
    nil = new nod(0, 0, 0, 0, 0);
    R = nil;
    for(int i = 1; i <= nr; i++)
        Insert (R, i - 1, v[i], Rand());
    build(R);
    int V = 0;
    scanf("%d", &M);
    for(int i = 1; i <= M; i++){
        int x;
        scanf("%d", &x), x ^= V;
        nod *R;
        det_root(adresa1[x], R);
        printf("%d\n", R->nr / 2), scos[x] = 1, V = R->nr / 2;
        for(auto it = muchii[x].begin (); it != muchii[x].end (); it ++)
            if (!scos[*it]) Del(x, *it);
    }
    return 0;
}

Tree Splitting Java Solution

import java.io.*;
import java.util.*;

public class Solution {

  static long x = 1;  
  // Xorshift random number generators
  static long marsagliaXor32() {
    x ^= x << 13;
    x ^= x >> 17;
    return x ^= x << 5;
  }


  static class Node {
    int size = 1;
    long pri = marsagliaXor32();
    Node l = null;
    Node r = null;
    Node p = null;

    Node mconcat() {
      this.size = size(l) + 1 + size(r);
      if (l != null) {
        l.p = this;
      }
      if (r != null) {
        r.p = this;
      }
      return this;
    }
  }

  static int size(Node x) {
    return x != null ? x.size : 0;
  }

  static Node root(Node x) {
    while (x.p != null) {
      x = x.p;
    }
    return x;
  }

  static long orderOf(Node x) {
    long r = size(x.l);
    while (x.p != null) {
      if (x.p.r == x) {
        r += size(x.p.l) + 1;
      }
      x = x.p;
    }
    return r;
  }

  
  static Node join(Node x, Node y) {
    if (x == null) return y;
    if (y == null) return x;
    if (x.pri < y.pri) {
      x.r = join(x.r, y);
      return x.mconcat();
    } else {
      y.l = join(x, y.l);
      return y.mconcat();
    }
  }

  static long[] dep;
  static List<Integer>[] es;
  static Node[] pre;
  static Node[] post;
  static Node tr = null;

  static class NodeDfs {
    int u;
    int p;
    boolean start = true;

    public NodeDfs(int u, int p) {
      this.u = u;
      this.p = p;
    }
  } 
  
  static void dfs(int u, int p) {
    Deque<NodeDfs> queue = new LinkedList<>();
    queue.add(new NodeDfs(u, p));
    while (!queue.isEmpty()) {
      NodeDfs node = queue.peek();
      if (node.start) {
        pre[node.u] = new Node();
        tr = join(tr, pre[node.u]);
        for (int v: es[node.u]) {
          if (v != node.p) {
            dep[v] = dep[node.u] + 1;
            queue.push(new NodeDfs(v, node.u));
          }
        }
        node.start = false;
      } else {
        post[node.u] = new Node();
        tr = join(tr, post[node.u]);
        queue.remove();
      }
    }
  }

  static Node[] split(Node x, long k, Node l, Node r) {
    if (x == null) {
      l = r = null;
    } else {
      long c = size(x.l) + 1;
      if (k < c) {
        Node[] res = split(x.l, k, l, x.l);
        l = res[0];
        x.l = res[1];
        r = x;
      } else {
        Node[] res = split(x.r, k - c, x.r, r);
        x.r = res[0];
        r =  res[1];
        l = x;
      }
      x.mconcat();
      x.p = null;
    }
    return new Node[] {l , r};
  }
  
  static void cut(int u, int v) {
    if (dep[v] < dep[u]) {
      int t = v;
      v = u;
      u = t;
    }
    long il = orderOf(pre[v]);
    long ir = orderOf(post[v])+1;
    Node y = root(pre[v]);
    Node z = null;
    Node[] res = split(y, ir, y, z);
    y = res[0];
    z = res[1];
    Node x = null;
    res = split(y, il, x, y);
    x = res[0];
    join(x, z);
  }

  
  public static void main(String[] args) throws IOException {
    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    BufferedWriter bw = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));

    StringTokenizer st = new StringTokenizer(br.readLine());
    int n = Integer.parseInt(st.nextToken());

    dep = new long[n];
    es = new List[n];
    pre = new Node[n];
    post = new Node[n];

    for (int i = 0; i < n; i++) {
      es[i] = new ArrayList<>();
    }
    for (int i = 0; i < n - 1; i++) {
      st = new StringTokenizer(br.readLine());
      int u = Integer.parseInt(st.nextToken())-1;
      int v = Integer.parseInt(st.nextToken())-1;
      es[u].add(v);
      es[v].add(u);
    }
    dfs(0, -1);

    st = new StringTokenizer(br.readLine());
    int queriesCount = Integer.parseInt(st.nextToken());

    int result = 0;
    for (int i = 0; i < queriesCount; i++) {
      st = new StringTokenizer(br.readLine());
      int u = Integer.parseInt(st.nextToken());
      u = (result ^ u) - 1;
      result = size(root(pre[u])) / 2;
      bw.write(String.valueOf(result));
      if (i != queriesCount - 1) {
        bw.write("\n");
        for (int v: es[u]) {
          cut(u, v);
        }
      }
    }

    bw.newLine();
    bw.close();
    br.close();
  }
}
c C++ HackerRank Solutions java