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What is a Mole? Learn Formula and Easy Ways to Calculate Moles

Yashwant Parihar, April 16, 2026April 16, 2026

The mole is one of the most important concepts in chemistry, but it can seem confusing at first. In simple words, a mole helps us count very tiny particles like atoms and molecules easily. Just like we use a dozen to count 12 items, chemists use the mole to count particles. In this post, you will learn what a mole is and explore simple methods to calculate moles using easy formulas and examples.

What is a Mole?

A mole is the amount of substance that contains as many species (atoms, molecules, ions and other species) as there are atoms in exactly 12g of C-12.

Mass of one atom of C-12 = 1.99×10-23g

No of atoms in 12g of C-12 = 12/1.99×10-23g
= 6.022×1023 g (Avagadron’s Number NA)

One mole is the collection of 6.022×1023 g particles. (atoms, molecules, ions, etc.)
1 mol of Na = 6.022×1023 g atoms of Na
1 mol of H2 gas = 6.022×1023 g molcules of H2
1 mol of NaCl = 6.022×1023 g formula unit of NaCl
1 mol of Cl– = 6.022×1023 g ions of Cl–

Molar Mass

It is the mass of one mole of substance.

For atoms: Molar Mass = Gram Atomic Mass
For Molecules: Molar Mass = Gram Molecular Mass

Molar Mass of He = 4g/mol
Molar Mass of Oxygen = 16g/mol

Methods to Calculate Moles

In Terms of Mass:

Numberofmoles=GivenmassofsubstanceMolarmassofsubstanceNumber\:of\:moles\; = \frac {Given\:mass\:of\:substance}{Molar\:mass\:of\:substance}


For example:

Convert 36g of Carbon into moles?

Numberofmoles=3612=3molNumber\:of\:moles\; = \frac {36}{12} = 3\:mol

In Terms of the number of Particles:

Numberofmoles=Givennumberofparticles6.022×1023gNANumber\:of\:moles\; = \frac {Given\:number\:of\:particles}{6.022\times10^{23} g\:N_A}

For example:

Convert 6.022×1021 atom of H into moles?\

Numberofmoles=6.022×10216.022×1023gNA=10−2Number\:of\:moles\; = \frac {6.022\times10^{21}}{6.022\times10^{23} g\:N_A} = 10^{-2}

In terms of Volume of Gas:

At STP(Standard Temperature and Pressure):

Old STP = T = 0o C = 273.15K
P = 1 atm
New STP = T = 0o C = 273.15K
P = 1 bar

1 atm = 1.012 bar
1 bar = 0.987 atm

From the ideal gas equation, PV = NRT
0.987 x V = 1 x 0.087 x 273.15K
V = 22.7L
Old STP, PV = NRT
1 x V = 1 x 0.087 x 273.15K
V = 22.4L

Numberofmoles=volumeofgasatSTPcondtions22.7/22.4Number\:of\:moles\; = \frac {volume\:of\:gas\:at\:STP\:condtions}{22.7/22.4}

Y-Map to Calculate the Moles

Y-Map to calculate moles
Chemistry class 11 Chemistry

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