Formula Sheet: Mechanical Properties of Solid Class 11 Yashwant Parihar, April 27, 2026May 4, 2026 In this post, we will learn about the formulas of Chapter 8, Class 11, Mechanical Properties of Solid with the help of the formula Sheet. We provide a comprehensive Mechanical Properties of Solids formula sheet that covers all elastic moduli, Poisson’s ratio, and energy density equations. Use this complete list to master the NCERT and solve numerical problems with accuracy.Table of Contents Mechanical Properties of Solids Formula Sheet1. Stress and Strain2. Hook’s Law and Modulus of Elasticity3. Poisson’s Ratio4. Elastic Potential Energy5. Relations between Elastic Constants (JEE/NEET Specials)Mechanical Properties of Solids Formula Sheet1. Stress and StrainNormal Stress:σ=F|A\sigma = \frac{F_|}{A}Shearing Stress:σ=F||A\sigma = \frac{F_{||}}{A}Longitudinal Strain:ϵ=ΔLL\epsilon = \frac{\Delta L}{L}Volume Strain:ΔVV\frac{\Delta V}{V}Shearing Strain:tanθ∼∼θ=ΔxLtan\theta \sim\sim \theta = \frac{\Delta x}L2. Hook’s Law and Modulus of ElasticityHook’s Law:Stress∝StrainStress \propto StrainYoung’s Modulus:Y=LogitudnalStressLongitudnalStrain=FLAΔLY =\frac{Logitudnal\: Stress}{Longitudnal\:Strain} = \frac{FL}{A\Delta L}Bulk Modulus:B=−pΔV/VB = -\frac{p}{\Delta V/V}The negative sign shows a decrease in volume as pressure increases.Compressibility:C=1BC = \frac{1}{B}Shear Modulus/Modulus of Rigidity:η=ShearingStressShearingStrain=FAθ\eta = \frac {Shearing\:Stress}{Shearing\: Strain} = \frac{F}{A\theta}3. Poisson’s Ratio The ratio of lateral strain to longitudinal strain.σ=LateralStrainLongitudnalStrain=−Δd/dΔL/L\sigma = \frac{Lateral\:Strain}{Longitudnal\:Strain} = \frac {-\Delta d/d}{\Delta L/L}Theoretical limits: -1 to 0.5Practical limits: 0 to 0.54. Elastic Potential EnergyEnergy stored in a stretched wire:Work done:W=12×Stress×Strein×VolumeW = \frac{1}{2} \times Stress \times Strein \times VolumeEnergy Density:u=12×Stress×strain=12Y(Strain)2u = \frac 1 2 \times Stress \times strain = \frac 12 Y (Strain)^25. Relations between Elastic Constants (JEE/NEET Specials)Y=3B(1−2σ)Y = 3B(1-2\sigma)Y=2η(1+σ)Y = 2\eta (1 + \sigma)σ=3B−2η2η+6B\sigma = \frac {3B-2 \eta}{2 \eta + 6B} Formula Sheet Physics Formula Sheet Formula SheetPhysics Formula Sheet