All Motion in a Straight Line Formulas for Class 11, JEE & NEET Yashwant Parihar, April 25, 2026April 25, 2026 In this post, we will learn all the formulas of Chapter 2, Class 11 motion in a straight line with the help of formula cheat sheets. We have written all the formulas—from the basic kinematic equations to advanced calculus-based derivations and motion under gravity. Bookmark this page and download the PDF version to ensure you never miss a mark in your JEE, NEET, or School Board exams!Complete List of Motion in a Straight Line Formulas1. Basic Kinematics FormulaDisplacement (Δx):Δx=xfinal−xinitialΔx = x_{final} – x_{initial}Average Velocity (Vavg):Vavg=TotalDisplacementTotalTimeV_{avg} = \frac{Total\:Displacement}{Total\:Time}Average Speed:Avg.Speed=TotalDistanceTotalTimeAvg.\: Speed = \frac{Total\:Distance}{Total\:Time}Instantaneous Velocity (v):v=dxdtv = \frac{dx}{dt}Instantaneous Acceleration (a):a=dvdt=d2xdt2a = \frac{dv}{dt} = \frac{d^2x}{dt^2}2. Equations of Motion (Constant Acceleration ONLY)First Equation:v=u+atv = u + atSecond Equation:s=ut+12at2s = ut + \frac{1}{2}at^2Third Equation:v2=U2+2asv^2 = U^2 + 2asFourth Equation (Displacement in nth second):Sn=u+a2(2n−1)S_n = u + \frac{a}{2}(2n – 1)3. Motion Under Gravity (Free Fall)Time to reach Max Height:t=ugt = \frac{u}{g}Maximum Height Reached (H):H=u22gH = \frac{u^2}{2g}Total Time of Flight (Up and Down):T=2ugT = \frac{2u}{g}Velocity on hitting the ground:v=2gHv = \sqrt{2gH}4. Important Shortcuts & Special CasesIf a car applies the brakes,ds=u22ad_s = \frac{u^2}{2a}Galileo’s Law of Odd Numbers: For an object starting from rest, the distances covered in equal time intervals follow the ratio 1 : 3 : 5……Relative Velocity: The velocity of object A with respect to object B is:VAB=VA−VBV_{AB} = V_A – V_B5. Calculus Methods (Variable Acceleration)Find v from a:v=∫adtv = \int adtFind s from v:s=∫vdts = \int vdtAcceleration as a function of x:a=vdvdxa = v\frac{dv}{dx} JEE JEE Physics JEEJEE Physics